Aspring of spring constant k = 340 nm-1 is used to launch a 1.5-kg block along a horizontal surface by compressing the spring by a distance of 18 cm. if the coefficient of sliding friction between the block and the surface is 0.25, how far does the block slide?

The block slides 1.5m

Explanation:

To solve this problem we need the concepts relate to work energy, work done, frictional force and normal force.

We know for definition that,

Where W is the work and \Delta KE the change in Kinetic Energy, F the force and d the distance.

The expression is relate to the Hook's law where F=kx, being k the elastic constant and x the displacement of the object.

We know as well that Frictional Force is given by

Where is the coefficient of friction, m the mass and g the gravity acceleration.

We can now solve the problem. Using the first equation we have,

Using the second form for work,

Here we know that is zero and F_f is equal to mg

Re-arrange for d,

Replacing the values we have,

The block slides 1.5m

he . if i may ask what i your question exactly?

explanation:

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.