Ask your teacher a circular wire loop whose radius is 10.0 cm carries a current of 3.60 a. it is placed so that the normal to its plane makes an angle of 39.0° with a uniform magnetic field of 12.0 t. (a) calculate the magnetic dipole moment of the loop.

Explanation:

Given that,

Radius of the circular loop, r = 10 cm = 0.1 m

Current flowing in the loop, I = 3.6 A

Uniform magnetic field, B = 12 T

To find,

The magnetic dipole moment of the loop.

Solution,

Let M is the magnitude of magnetic dipole moment of the loop. We know that the product of current flowing and the area of cross section. Its formula is given by :

A is the area of circular wire

Therefore, the magnetic dipole moment of the loop is . Hence, this is the required solution.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.