Constant-volume calorimeters are sometimes calibrated by running a combustion reaction of known δe and measuring the change in temperature. for example, the combustion energy of glucose is 15.57 kj/g. when a 2.000 g sample of glucose burns in a constant volume calorimeter, the calorimeter temperature increases from 21.45 to 23.34°c. find the total heat capacity of the calorimeter (in kj/k).

0.1132 kJ/K the total heat capacity of the calorimeter.

Explanation:

The combustion energy of glucose = 15.57 kJ/g.

Energy released on 2 combustion of 2.000 g of glucose = Q

Q=31.140 kJ

Heat gained by the calorimeter = Q'

Heat gained by the calorimeter = heat released on combustion of glucose

Q'= 31.140 kJ

Temperature change of the calorimeter = ΔT = 23.34°C - 21.45°C = 1.89°C

ΔT = 1.89°C = 275.04 K

Total heat capacity of the calorimeter = C

0.1132 kJ/K the total heat capacity of the calorimeter.

the speed of the cart after 3 seconds of low fan speed is ⇒ 54.0 cm/s.

the speed of the cart after 5 seconds of medium fan speed is ⇒ 120.0 cm/s.

the speed of the cart after 2 seconds of high fan speed is ⇒ 64.0 cm/s. 

just did the lab.