Three children are riding on the edge of a merry-go-round that is 105 kg, has a 1.40-m radius, and is spinning at 16.0 rpm. the children have masses of 22.0, 28.0, and 33.0 kg. if the child who has a mass of 28.0 kg moves to the center of the merry-go-round, what is the new angular velocity in rpm? ignore friction, and assume that the merry-go-round can be treated as a solid disk and the children as points.

20.16744 rpm

Explanation:

Initial angular momentum=Final angular momentum

Initial angular momentum= w1 hence where w1 is initial rate of rotation/ velocity, m is mass of merry go round, m1 is mass of first child, m2 is mass of second child, m3 is mass of the third child, r is the radius of merry go round

Final angular momentum=

Substituting 105 Kg for m, 1.4 m for r, 16 rpm for w1, 22 Kg for m1, 28 Kg for m2, 33 Kg for m3 we obtain

1.4*16*((0.5*105)+{22+28+33})=1.4*w2((0.5*105)+{22+33})

W2=20.16744 rpm

b mirrors submit a iisner? e. for which optical devices does d sometimes have a positive value? o a a and b o b. a and c o c. b and d 0 d. b and cb

if they have a finite resultant