A57 kg woman is on an elevator accelerating upward at "1.25" meters per second squared. what is the normal force acting on her?

me with this have tried several answers! oh, and you.

Normal force acting on the woman is 629.85 N.

Explanation:

Given:

Mass of the woman is,

Net upward acceleration is,

Acceleration due to gravity,

Let the normal force acting upward be newtons.

Therefore, net force in the upward direction is given as:

Net force = Upward force - Downward force.

Downward force acting on the woman is her weight which is equal to .

Therefore, Net force =

Now, as per Newton's second law of motion,

Net force,

So,

Plug in 57 kg for , 9.8 m/s² for , and 1.25 m/s² for . Solve for . This gives,

Therefore, the normal force acting on her is 629.85 N.

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min