Abat strikes a 0.145-kg baseball. just before impact, the ball is traveling horizontally to the right at 55.0m/s , and it leaves the bat traveling to the left at an angle of 40? above horizontal with a speed of 60.0m/s . the ball and bat are in contact for 1.85ms .part afind the horizontal component of the average force on the ball. take the x-direction to be positive to the rightpart bfind the vertical component of the average force on the ball.

A. Fx = -7913.08 N

B. Fy = 3022.84 N

Explanation:

By conservation of the linear momentum:

ΔP = m*(Vf - Vo) = F*Δt

where:

m = 0.145 kg

Vf = [-60*cos(40°), 60*sin(40°)] m/s

Vo = [55, 0] m/s

F = [Fx, Fy]

Δt = 0.00185 s

With these values we can solve for F on both axis.

On the x-axis:

On the y-axis:

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

reserve is the answer