Consider a long, closely wound solenoid with 10,000 turns per meter. what current, in amperes, is needed in the solenoid to produce a magnetic field inside the solenoid, near its center, that is 104 times the earth’s magnetic field of 4.95 × 10-5 t?

0.4344A

Explanation:

From Ampere's law, it can be shown that the magnetic field B inside a long solenoid is

Where

B= Magnetic field strenght at distance d

I= current

Permeability of free space ()

N= Number of loops

Our values are defined as follow,

T

As a current required to become 104 times the Earth's magnetic field is required, we use B '

Therefore is needed 0.4344A in the solenoid to produce a magnetic field inside the solenoid, near its center, that is 104 times the Earth's magnetic field.

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