In a physics lab, asha is given a 10.5 kg uniform rectangular plate with edge lengths 66.3cm by 52.1cm . her lab instructor requires her to rotate the plate about an axis perpendicular to its plane and passing through one of its corners, and then prepare a report on the project. for her report, asha needs the plate's moment of inertia with respect to given rotation axis. calculate .

The plate's moment of inertia is 2.489 kg * m²

Explanation:

Step 1: Data given

mass of the uniform rectangular plate = 10.5 kg

lengths of the plate = 66.3cm by 52.1cm

Step 2: Calculate moment of inertia

For an axis through the center of the rectangle, I = m[(w²+L²)/12

Using the parallel axis theorem, the added value of I = mR² = m[(w²/4 + L²/4]

IF we get both reactions together we get:

I = (m/3)*(w²+L²)

I = 10.5/3 *(0.663² + 0.521²)

I = 2.489 kg * m²

The plate's moment of inertia is 2.489 kg * m²

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.