An electron that has a velocity with x component 2.6 × 106 m/s and y component 4.0 × 106 m/s moves through a uniform magnetic field with x component 0.037 t and y component -0.17 t. (a) find the magnitude of the magnetic force on the electron. (b) repeat your calculation for a proton having the same velocity.

Explanation:

It is given that,

The horizontal and vertical component of velocity of an electron is:

The magnetic field acting there is given by :

(a) The magnitude of the magnetic force on the electron is given by :

q = e

(b) We know that the charge on proton is :

The magnetic force as same as for electron but the direction is opposite i.e.

Hence, this is the required solution.

answer; /// the above statement is (true);

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