A195 g block is pressed against a spring of force constant 1.60 kn/m until the block compresses the spring 10.0 cm. the spring rests at the bottom of a ramp inclined at 60.0° to the horizontal. using energy considerations, determine how far up the incline (in m) the block moves from its initial position before it stops under the following conditions(a) if the ramp exerts no friction force on the block(b) if the coefficient of kinetic friction is 0.440 tm(c)what if? if the ramp is 4.00 m long, what is the maximum coefficient of friction that would allow the block to reach the end of the ramp?

a). d=4.83m

b). d=3.876m

c). u=0.361

Explanation:

The blocks stops moving up the ramp when all the elastics Energy (Ek) in the spring has transfer to Energy gravity (Ep)

So using the law conservation of energy and in the motion

Energy Kinetic is the energy of the spring so 'K' is the force constant and xk is the distance the block compresses the spring and 'h' is the height for a ramp 60 angle so:

a).

Solving for 'd'

b).

Now the force of friction is acting so the Ep add the force

Get the factor to resolve d

c).

Finally if the distance of the rampo is knowing determinate the u coefficient of friction can be find

i think the correct answer from the choices listed above is option c. when the kinetic energy of particles in a liquid state decreases

explanation: