The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the plane of the equator. assuming the earth is a sphere with a radius of 6.38 × 106 m, determine the speed and centripetal acceleration of a person situated (a) at the equator and (b) at a latitude of 30.0° north of the equator.

Answer

given,

Radius of earth = 6.38 x 10⁶ m

angular velocity  =

                            =

                            =

a) at equator

velocity v   = R ω  = 6.38 x 10⁶ x 7.27 x 10⁻⁵

             v = 463.8 m/s

centripetal acceleration = R ω² = 6.38 x 10⁶ x (7.27 x 10⁻⁵)²

                                        = 0.0337 m/s²

b) at a latitude of 30.0° north of the equator

r = R cos θ  =  6.38 x 10⁶ cos 30⁰ =  3.19 x  10⁶ m

velocity v   = R ω  = 3.19 x  10⁶ x 7.27 x 10⁻⁵

            v = 231.9 m/s

centripetal acceleration = R ω² = 3.19 x  10⁶  x (7.27 x 10⁻⁵)²

                                        = 0.0168 m/s²

the answer is mosques. they are an important part of islamic culture.

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.