Acircuit consists of a series combination of 6.00 −kω and 4.50 −kω resistors connected across a 50.0-v battery having negligible internal resistance. you want to measure the true potential difference (that is, the potential difference without the meter present) across the 4.50 −kω resistor using a voltmeter having an internal resistance of 10.0 kω. what potentialdifference does the voltmeter measure across the 4.50-kωresistor?

17.05V

Explanation:

Hello!

To solve this exercise we will use the following steps, the complete procedure attached an image.

1. Draw the complete circuit taking into account the configuration of the problem.

2. Remembering that the voltages in the nodes of the

Resistances connected in parallel are equal, we put them together using the sum of their inverses to find an equivalent resistance.

3. We find the current flowing in the circuit by taking the voltage from the source and dividing it by the total sum of resistances using Ohm's law

4. We use ohm's law again to find the voltage at the equivalent resistance.

Note: Ohm's law states that the voltage at a resistance is equal to the product of the current by the value of the resistance.

regards!

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards