Two sides of a triangle are 8 m 8 m and 10 m 10 m in length and the angle between them is increasing at a rate of 0.06 rad/s 0.06 rad/s. find the rate at which the area of the triangle is increasing when the angle between the sides of fixed length is π 3 rad π3 rad.

the rate at which the area of the triangle is increasing is

Explanation:

The area A of the triangle is given by:

A = (1/2)bh

Where b is the base of the triangle and h is the height of the triangle. if we know 2 sides of the triangle, we can define b and h using the attached image as:

b = 10 m

h =  8 sen(x)

Where x is the angle between the sides of fixed length. So the Area of the triangle is:

A = (1/2)(10)(8*sen(x))= 40*sen(x)

Then, if we derive the equation of the area with respect to the time, we get:

Where is the rate of the increasing angle.

So, if we replace this by 0.06 rad/s, we get:

So, if x is equal to π/3, the rate at which the area of the triangle is increasing is:

=2.4cos(π/3)

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j