A35 kg box rests on the back of a truck. the coefficient of static friction bet? 005 (part 1 of 2)a 35 kg box rests on the back of a truck. thecoefficient of static friction between box andtruck bed is 0.202.the acceleration of gravity is 9.8 m/s2 .when the truck accelerates forward, whatforce accelerates the box? 006 (part 2 of 2)
what maximum acceleration can the truck
have before the box slides?
answer in units of m/s2.

Answer with Explanation:

We are given that

Mass of box=35 kg

Coefficient of static friction between box and truck bed=0.202

Acceleration due to gravity=

a.We have to find the force by which the box accelerates forward.

Force by which box accelerates=

Force by which box accelerates=

b.We have to find the maximum acceleration can the truck have before the box slides.

Force =friction force

Hence, the truck can have maximum acceleration before the box slide=

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000