(a) a 22.0-kg child is riding a playground merry-go-round that is rotating at 40.0 rev/min. what centripetal force is exerted if he is 1.25 m from its center? (b) what centripetal force is exerted if the merry-go-round rotates at 3.00 rev/min and he is 8.00 m from its center? (c) compare each force with his weight.

a)  F₁ = 483 N, b) F₂ = 176 N  and c)  F₁ / W = 2.2 ,    F₂ / W = 0.82

Explanation:

To find force we use Newton's second law, where acceleration is centripetal

    F = m a

The centripetal acceleration is

    a = v² / r

The relationship between linear and angular velocity is

    v = w r

Substituting Newton's law

    F = m (w r)² / r

    F = m w² r

Let's calculate for each case

a) Let's reduce the units to the SI system

      w = 40.0 rev / min (2pi rad / rev) (1min / 60s)

      w = 4,189 rad/s

      F₁ = 22.0 4.189² 1.25

      F₁ = 482.6 N

      F₁ = 483 N

b)   w = 3.00 rev / min = 0.314 rad / s

     F₂ = 22.0 0.314 2 8.00

     F₂ = 176 N

c) the child's weight is

    W = m g

    W = 22.0 9.8

    W = 215.6 N

To make this comparison we can divide the two quantities

    F₁ / W = 483 / 215.6

    F₁ / W = 2.2

   F₂ / W = 176 / 215.6

   F₂ / W = 0.82

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

happy to

pls mark as brainliest.