Arocket is launched at an angle of 39◦ above the horizontal with an initial speed of 90 m/s. it moves for 7 s along its initial line of motion with an acceleration of 19 m/s 2 . at this time its engines fail and the rocket proceeds to move as a projectile. the acceleration of gravity is 9.8 m/s 2 . find the maximum altitude reached by the rocket. answer in units of m.

Y=1370.23m

Explanation:

The motion have two moments the first one the time the initial velocity is accelerating then when the engines proceeds to move as a projectile

Now the motion the rocket moves as a projectile so:

Now the final velocity is the initial in the second one

The maximum altitude Vf=0

So total altitude is both altitude of the motion so:

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle