A32-g chunk of chilled glass at 12°c is dropped into 54 g of water at 37°c. what is the equilibrium temperature of the system? the specific heats of glass and water are 0.840 and 4.186 j/(g×°c), respectively.

The equilibrium temperature of the system is 29.9°C

Explanation:

When chilled glass is dropped in water, the amount of heat released by water will be equal to the amount of heat absorbed by glass.

The equation used to calculate heat released or absorbed follows:

     ......(1)

where,

q = heat absorbed or released

= mass of glass = 32 g

= mass of water = 54 g

= final temperature = ? °C

= initial temperature of glass = 12°C

= initial temperature of water = 37°C

= specific heat of glass =  0.840 J/g°C

= specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

Hence, the equilibrium temperature of the system is 29.9°C

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

it becomes positively charged by charging it