In a lab experiment, two identical gliders on an air track are held together by a piece of string, compressing a spring between the gliders. while they are moving to the right at a common speed of 0.420 m/s, one student holds a match under the string and burns it, letting the spring force the gliders apart. one glider is then observed to be moving to the right at 1.300 m/s. (the string and spring both have negligible mass). what velocity does the other glider have? enter a positive value if the velocity is toward right and enter a negative value if the velocity is toward left.

= -0.460 m/s

Explanation:

To solve this problem we will use the concept of moment, write the initial amount when they are united and the end

Initial. Before break away

    p₀ = (m + m) v₀

Final. After separating

    = m + m

   p₀ =

   (m + m) v₀ = m + m

They tell us that when they go together the speed vo = 0.420 m / s and after separating one we will call 2 has a speed of v2f = 1,300 m / s. let's look for each other's speed

    m = (2m) vo - m

    = 2 v₀ -

    = 2 0.420 - 1.300

    = -0.460 m/s

The negative sign indicates that it moves to the left

the answer is a. hope this .

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y