A57 g tennis ball is traveling at 45 m/s to the right, when it hits a racket. the ball reversed direction and travels at 33 m/s. the ball is in contact with the racket for 0.0085 s.

what is the magnitude of the force that was exerted on the ball?

a. 1.8n
b. 12n
c. 81n
d. 520n

D. 520 N

Explanation:

According to the impulse theorem, the change in momentum of the ball is equal to the impulse exerted on the ball, mathematically:

where

is th change in momentum

F is the average force exerted on the ball

is the time of contact

The change in momentum of the ball is

where

m = 57 g = 0.057 kg is the mass of the ball

u = 45 m/s is the initial velocity

v = -33 m/s is the final velocity (in the opposite direction)

Substituting,

The time of the collision is

Therefore, the average force is

So, the magnitude is approximately 520 N.

unlike poles attract

0.19 m/s and 0.45 m/s