A5.0 kg box is sliding across a waxed floor by the application of a 15 n east force. if the force of friction is 2.5 n west, what is the net force acting on the box? whis is the box's acceleration

1) 12.5 N east

There are two forces acting on the box along the horizontal direction:

- The applied force of 15 N east, we indicate it with F

- The force of friction of 2.5 N west, we indicate it with

Taking east as positive direction, we can write the two forces has

Therefore, the net force on the box will be:

And the positive sign means the direction is east.

2)

We can solve this part by using Newton's second law:

where

is the net force on the box

m is its mass

a is the acceleration

For the box in this problem,

(east)

m = 5.0 kg

Solving for a, we find the acceleration:

And the direction is the same as the net force (east)

f=ma newton's second law 7x8=56n

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