In punting a football, the kicker tries to maximize both the distance of the kick and its "hang time"—the time that the ball is in the air. a kicker gets off a great punt with a hang time of 5.0 s that lands 50 yards from the kicker. what is the speed of the ball as it leaves the kicker’s foot?

v₀ = 26.17 m/s

Explanation:

If

R = Xmax = 50 yards = (50 yards)*(0.9144 m / 1 yard) = 45.72 m

t = 5 s  (Time of Flight)

we can apply the equation:

R = V₀x*t  ⇒   V₀x = R / t = 45.72 m / 5 s   ⇒   V₀x = 9.144 m/s

then we use the equation of Time of Flight:

t = 2*V₀y / g   ⇒    V₀y = g*t / 2 = (9.81 m/s²)*(5 s) / 2  ⇒    V₀y = 24.525 m/s

Finally we apply

v₀ = √(V₀x² + V₀y²)   ⇒   v₀ = √(9.144² + 24.525²) m/s

⇒   v₀ = 26.17 m/s

wavelength divides in half and speed stays the same.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force