You have two strings of length 0.5 m. both strings are fixed at both ends and have tension 10 n. the first string has a mass of 0.5 kg and the second has a mass of 2.5 kg. for each string, calculate the wavelength and frequency of the fundamental resonance and the next resonance (which has a shorter wavelength). draw the wavelengths for each. if string 1 played its fundamental, would string 1 start to vibrate? if string 2 played its fundamental, would string 1 start to vibrate? if so, at what frequency? if you had another source, at what frequency or frequencies could it vibrate to make string 1 vibrate?

Since the pully is a simple machine so the mechanical advantage is a 1

Ithink the answer is c. make unnecessarily  wide gestures 

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Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.