Train cars are coupled together by being bumped into one another. suppose two loaded train cars are moving toward one another, the first having a mass of 1.62 ✕ 105 kg and a velocity of (0.30 m/s)î, and the second having a mass of 1.11 ✕ 105 kg and a velocity of −(0.12 m/s)î. what is their final velocity (in m/s)? (express your answer in vector form.)

Explanation:

It is given that,

Mass of the car 1,

Initial speed of the car 1,

Mass of the car 2,

Initial speed of the car 2,

It is mentioned that train cars are coupled together by being bumped into one another. Let V is the final velocity of the train cars after the collision. It can be calculated using the conservation of linear momentum as :

So, the final speed of the coupled train cars is 0.129 m/s towards x axis. Hence, this is the required solution.  

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂