One mole of a gas is placed in a closed system with a 20 l vessel initially at t = 300 k. the vessel is then isothermally expanded to 40 l. the gas follows the equation of state: p = rt/v + a/v2 where a = 240 l2 · atm/mol2 and r = 0.08206 l · atm/ mol · k. a. derive an expression relating (dh/dv)t to measurable properties. b. find dh for the gas in this process.

Given that

P = RT/V + a/V²

We know that

H= U + PV

For T= Constant  (ΔU=0)

ΔH= ΔU +Δ( PV)

ΔH= Δ( PV)

P = RT/V + a/V²

P V= RT + a/V

dH/dV = d(RT + a/V)/dV

dH/dV = - a/V²

So the expression of dH/dV

b)

In isothermal process

     (ΔU=0)

Now by putting the all values

ΔH = 17.06 L.atm

c. newton's third law of motion

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is