Ablock of aluminum at a temperature of t1 = 32 degrees c has a mass of m1 = 12 kg. it is brought into contact with another block of aluminum with a mass of m2 = 0.5m1, at a temperature of t2 = 9 degrees c. this aluminum has a heat capacity of c = 899 j/kg k.

Explanation:

Given

mass of First Block

Temperature

mass of second block

Temperature

Heat capacity of aluminium c=899 J/kg-K

Final Temperature acquired by both blocks at steady state

Heat loss first block =Heat gain by second block

unable to answer the rest since your question is incomplete

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000