An applied pulling force of 100 n is used to accelerate an object to the right along a rough surface that offers 40 n of frictional resistance if the normal force is 60n what is the acceleration of the object

Explanation:

First of all, we analyze the vertical direction.

Along this direction, the object is in equilibrium, so its acceleration is zero, and therefore  the net force on it is zero. There are only two forces acting on the object vertically: the weight, W (downward), and the normal force, N (upward), and since the net force must be zero, we can write

And since N = 60 N, the weight of the object is

W = 60 N

From this, we can also find the mass of the object, using the equation:

where is the acceleration of gravity.

Now we analyze the forces along the horizontal direction. We have:

A pulling force of F=100 N forward

A frictional resistance of backward

So the equation of motion in this direction is

And solving for a, we find the acceleration of the object:

in the horizontal direction, forward.

explanation:

newton's third law, for every action there is an equal and opposite reaction.

nah.   i'm just sleepy.