What fraction of the horse's weight is borne by the front hooves?

3056N

Explanation:

Torque =rF

Since left side of the torque=right side of the torque

1.1(5000-x)=(1.8-1.1)(x)

x(weight of the front side), x=3055.56

Fraction of the horses weight = (weight of the front side)/(total weight)

1.8m/1.1m = 1.636m

Then, 5000N/1.636m =3056N

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explanation:

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.