How far below an initial straight-line path will a projectile fall in one second

9.8 m

Explanation:

The rate of free fall of a body does not depend on its mass or shape in the absence of air resistance.  This property of gravitational force is proved by the famous leaning tower of Pisa experiment by Galileo.

The gravitational force is responsible for the gravitational acceleration of a body.

When considering the gravitational acceleration near the surface of Earth it has the constant value g = 9.8 m/s irrespective of the mass of the body.

This phenomenon states that every projectile falls at the same rate such that its velocity keeps on increasing to maintain the constancy of g.

So, when a projectile fall initially from a certain height for one second, it would have traveled only 9.8 m.

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation:

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards