Physics

preston tossed a red ball upward and it reaches a maximum height of 3.0m what is the final velocity when it returns to preston's hand?

7.75m/s

Explanation:

V^2=U^2 + 2gs

U is 0

so V^2=2gs

V^2=2×3×10

V^2=60

V=(60)^2

=7.74596692

the answer is 12 as i may remember

: )

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down