Physics question-does anyone know how to do this with the working

taking the resistivity of platinoid as 3.3 x 10-7 m, find the resistance of 7.0 m of platinoid wire of average diameter 0.14 cm.

Resistance of wire, R = 1.5 ohm

Explanation:

Given that,

The resistivity of the platinoid wire, ρ = 3.3 x 10⁻⁷  ohm - meter

Length of the platinoid wire, l = 7 meter

Diameter of the wire, d = 0.14 cm  =  0.0014 m

Radius of the wire, r = d/2 = 7 x 10⁻⁴  m

Therefore, core sectional area of the wire, A = π r²

                                                                    = 1.539 x 10⁻⁶   m²

According to Pouillet's law, the resistance of a wire is given by the relation,

Substituting the values in the above equation

                       R = 3.3 x 10⁻⁷

                           = 1.5 ohm

Hence, the resistance of the given platinoid wire is,  R = 1.5 ohm      

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm