Adisk of radius 25.0 cm is free to turn about an axle perpendicular to it through its center. it has very thin but strong string wrapped around its rim, and the string is attached to a ball that is pulled tangentially away from the rim of the disk. the pull increases in magnitude and produces an acceleration of the ball that obeys the equation where t is in seconds and a is a constant. the cylinder starts from rest, and at the end of the third second, the ball’s acceleration is 1.50 m/s^2.
(a) find a.
(b) express the angular acceleration of the disk as a function of time.
(c) how much time after the disk has begun to turn does it reach an angular speed of 14.5 rad/s ?
(d) through what angle has the disk turned just as it reaches 14.5 rad/s ?

Part a)

Part b)

Part c)

Part d)

Explanation:

Part a)

As we know that acceleration of the ball is given as

here we know that

at t = 3 s we have

so we will have

so we will have

Part b)

As we know that

here we have

R = 25 cm

so we will have

Part c)

now we know that

Part d)

As we know that

so we will have

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.