2. how many grams of water can be heated from 20.0°c to 75°c using

12500.0 joules?

W0lf93. energy flows from the producer level to the consumer level.

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.

Answer(b) both involve the use of levers;

B. elliptical. as in oval. 0 (==