Amercury manometer (rho = 13,600 kg/m3) is connected to an air duct to measure the pressure inside. the difference in the manometer levels is 30 mm, and the atmospheric pressure is 100 kpa. (a) judging from fig. p1–65, determine if the pres- sure in the duct is above or below the atmospheric pressure. (b) determine the absolute pressure in the duct

P = 104 kPa

Explanation:

a) To know if the pressure is higher or lower than the atmospheric, we only have to see the tubes if the right side is higher the pressure is higher than the atmospheric, otherwise it is lower.

b) The pressure in a system is

          P = + ρ g (Y2-y1)

Where is the atmospheric pressure in the open part of the tuno,ρ is the liquid density and (y2-y1) is the difference height between the two sides of the tube.

Let's reduce to SI units

         (y2-Y1) = 30 mm (1m / 1000 mm) = 30 10-3 m

        = 100 KPa = 100 10 3 Pa

Let's calculate the pressure

       P =    + 13.6 9.8 30 10⁻³

       P = 100 10³ + 3,998

       P = 103,998 Pa

      P = 104 kPa

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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