You have two resistors with the same cross sectional area and resistivity. resistor a has length l1 and resistor b has length l2. assume l2 > l1. if the resistors are connected in series with a battery, which resistor has the most power delivered to it? explain. b: if they are connected in parallel with a battery, which resistor has the most power delivered to it? explain.

Explanation:

Given

Resistor A has length

and Resistor B has Length

and Resistance is given by

Considering and A to be constant thus

because

(a)When they are connected in series

As the current in series is same and power is

therefore as R is greater for second resistor

(b)if they are connected in Parallel

In Parallel connection Voltage is same

resistance of 2 is greater than 1 thus Power delivered by 1 is greater than 2

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.