Asteel ball rolls with constant velocity on a tabletop 1.95 m high. it rolls off and hits the ground 0.5 m away from the edge of the table. how fast was the ball rolling?

0.79 m/s

Explanation:

First of all, we analyze the vertical motion of the ball. It is a free fall motion, so its vertical displacement is given by

where

s = 1.95 m is the displacement

u = 0 is the initial vertical velocity

t is the time

is the acceleration of gravity

Solving for t, we find the time it takes for the ball to reach the ground:

Now we can analyze the horizontal motion: this is a uniform motion with constant speed, so the horizontal distance covered by the ball is

where

d = 0.5 m is the horizontal distance covered

t = 0.63 s is the time

Solving for vx, we find the horizontal velocity of the ball:

And this velocity is constant during the motion, so the ball was moving at 0.79 m/s when it rolls off the table.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

i guess it’s a and b