Physics, 23.10.2019 05:00 jessica112776

A2.0-kg block is on a perfectly smooth ramp that makes an angle of 30° with the horizontal. (a) what is the block’s acceleration down the ramp and the force of the ramp on the block? (b) what force applied upward along and parallel to the ramp would allow the block to move with constant velocity?

Answers: 1

Show answers

Answers

Answer from: shelbylynn1093

The block’s acceleration down the ramp is 4.9m/s²

The force applied upward along and parallel to the ramp would allow the block to move with a constant velocity is 9.8 N

According to Newton's second law;

F_m = ma

Fm is the moving force

m is the mass of the block

a is the acceleration

Since the block acts along the ramp

$F_m = Wsin \theta\\F_m=mgsin \theta$

Given the following parameters

m = 2.0kg

g = 9.8m/s²

$\theta$ = 30 degrees

Get the required acceleration:

$a=\frac{F_m}{m}\\a=\frac{mgsin \theta}{m}\\a=gsin \theta$

Substitute the given parameters

$a=9.8sin30^0\\a=9.8(0.5)\\a=4.9m/s^2$

Hence the block’s acceleration down the ramp is 4.9m/s²

b) The force applied upward along and parallel to the ramp is the moving force along the plane expressed as:

$F_m=Wsin \theta\\F_m=2(9.8)sin30\\F_m=19.6(0.5)\\F_m=9.8N$

Hence the force applied upward along and parallel to the ramp would allow the block to move with a constant velocity is 9.8 N

Learn more here: link

Answer from: Shaynele

a) a = 4.9 m / s², N = 16.97 N and b) F = 9.8 N

Explanation:

a) For this exercise we will use Newton's second law, we write a reference system with the x axis parallel to the plane, see attached, in this system the only force we have to break down is weight, let's use trigonometry

sin 30 = Wx / W

cos 30 = Wy / W

Wx = W sin30

Wy = W cos 30

Let's write the equations on each axis

X axis

Wx = ma

Y Axis

N- Wy = 0

N = Wy = mg cos 30

N = 2.0 9.8 cos 30

N = 16.97 N

We calculate the acceleration

a = Wx / m

a = mg sin 30 / m

a = g sin 30

a =9.8 sin 30

a = 4.9 m / s²

b) For the block to move with constant speed, the acceleration must be zero, so the force applied must be equal to the weight component

F -Wx = 0

F = Wx

F = m g sin 30

F = 2.0 9.8 sin 30

F = 9.8 N

Answer from: Quest

Ifound this on google “your outer ear collects sound waves and reflects them into a tiny tube called the ear canal. at the end of the ear canal is a thin, skin-like membrane stretched tightly over the opening, called the eardrum.” i hope this you for what your looking for

Answer from: Quest

we need answer choices

Another question on Physics

Physics, 21.06.2019 20:30

3. on your graph, the data points between the black squares are data for elements with atomic numbers 3 through 9. locate these elements on your periodic table. what term or description would you use to identify these elements with respect to the periodic table?

Answers: 2

Answer

Physics, 22.06.2019 04:00

When the force acting on an object points at least partially in the direction of the motion the work done is considered to be negative

Answers: 2

Answer

Physics, 22.06.2019 07:00

Why should seat belts not be mandatory quick plz

Answers: 2

Answer

Physics, 22.06.2019 11:30

Two 1.20-m nonconducting wires meet at a right angle. one segment carries + 2.50 µc of charge distributed uniformly along its length, and the other carries - 2.50 µc distributed uniformly along it, as shown in fig. 21.50. ( a. find the magnitude and direction of the electric field these wires produce at point p, which is 60.0 cm from each wire. ( b. if an electron is released at p, what are the magnitude and direction of the net force that these wires exert on it?

Answers: 3

Answer

You know the right answer?

A2.0-kg block is on a perfectly smooth ramp that makes an angle of 30° with the horizontal. (a) what...

Questions