Aball is thrown horizontally from the top of a building 18.4 m high. the ball strikes the ground at a point 79.2 m from the base of the building. the acceleration of gravity is 9.8 m/s. find the time the ball is in motion. answer in units of s.

1.94 s

Explanation:

To find the time of flight of the ball, we can just analyze its vertical motion.

The motion of the ball is a free fall motion, which is a uniform accelerated motion. Therefore we can use the suvat equation:

where

s is the vertical displacement

u = 0 is the initial vertical velocity of the ball

t is the time

is the acceleration of gravity

Chosing downward as positive direction,

s = 18.4 m

And solving for t, we find the time during which the ball is in motion:

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this