Two points, point a and point b, are situated above a current-carrying wire. point b is located at a distance r from the wire, which is twice as far from the wire as point a. by what factor is the magnetic field at point a larger or smaller than the magnetic field at point b?

Explanation:

It is given that, there are two points situated above a current-carrying wire. Point B is located at a distance R from the wire, which is twice as far from the wire as point A such that,

And

We know that the magnetic field at a distance R is inversely proportional to the distance from wire as :

So, the magnetic field at point A larger than the magnetic field at point B by a factor of 2. Hence, this is the required solution.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j