What is the net force exerted by these two charges on a third charge q3 = 54.5 nc placed between nc and nc at x3 = -1.145 m ? your answer may be positive or negative, depending on the direction of the force.

because if the tool that you are using is not balanced it there would be false mass.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j