Calculate the electric force that exists between two objects that are 0.900 m
apart and carry charges of 0.00150 c and 0.00340 c. is this force attractive or
repulsive?

answer:

the electric force is 4,08e-5 joules

explanation:

we use the formula

e= 1/2 x q x v   , q being the charge stored in each capacitor plate and v the voltage applied to the plates

e =1/2 x (3,4 e-6 c) x (24 v) = 4,08 x-5 j

the unit joule equals coulomb x volt

any one of the statements could be an accurate comparison. but the statement that would define the correct choice and seal the deal is not even on the list:

"the visibilities of vector-x and vector-y in the drawing provided with the question are identical and nonexistent."

explanation:

could i give you a exaplo that could you?