Use the energy equation from this week’s notes, your answer from #5, and plank’s constant (6.63e-34) to find the approximate energy of this photon:

4.8e-19 joules

3.0e-19 joules

3.0e-17 joules

1.21 gigawatts

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

That would be kinetic energy