The cosmoclock 21 ferris wheel in yokohama city, japan, has a diameter of 100 m. its name comes from its 60 arms, each of which can function as a second hand (so that it makes one revolution every 60 s).
part a: find the speed of the passengers when the ferris wheel is rotating at this rate (in m/s)
part b: a passenger weighs 834 n at the weight-guessing booth on the ground. what is his apparent weight at the highest point of the ferris wheel? (in n)
part c: what is his apparent weight at the lowest point on the ferris wheel?
part d: what would be the time for one revolution if the passeger's apparent weight at the highest point were zero? (in s)
part e: what then would be the passenger's apparent weight at the lowest point? (in n)

Explanation:

A ) angular velocity ω = 2π / T

= 2 x 3.14 / 60

= .10467 rad / s

linear velocity v = ω R

=  .10467 x 50

= 5.23 m / s

centripetal force = m v² / R

= mg v² / gR

= 834 x 5.23² / 9.8 x 50

= 46.55 N

B )

apparent weight

= mg - centripetal force

= 834 - 46.55

= 787.45 N

C ) apparent weight

= mg + centripetal force

= 834 + 46.55

= 880.55 N.

D )

For apparent weight to be zero

centripetal force = mg

mg = mv² / R

v² = gR

= 9.8 x 50

= 490

v = 22.13 m /s

time period of revolution

= 2π R /v

2 x 3.14 x 50 / 22.13

= 14.19 s  

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

read more on -

electrical power