At the instant a traffic light turns green, a car starts with a constant acceleration of 1.3 m/s2. at the same instant a truck, traveling with a constant speed of 7.0 m/s, overtakes and passes the car.
(a)how far beyond the traffic signal will the car overtake the truck?
(b)what will the velocity of the car be at that instant?

(a) Distance traveled = 75.3846 m

(b) Velocity of car at that instant will be 14 m/sec

Explanation:

We have given acceleration of the car

Initial velocity of the cart u = 0 m/sec

(a) According to second equation of motion we know that

So distance traveled by car

As the truck is moving with constant speed

So distance traveled by truck

As the truck overtakes the car

So

So distance traveled

(b) From second equation of motion we know that v = u+at

So v = 0+1.3×10.769 = 14 m /sec

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length

cant without the picture! ?