As the earth rotates, what is the speed of a physics student in miami, florida, at latitude 26∘? ignore the revolution of the earth around the sun. the radius of the earth is 6400 km. express your answer with the appropriate units. vstudent = 416 ms

Explanation:

given,

Radius of earth = 6400 Km

speed of a physics student in Miami, Florida, at latitude 26° = v

time period of rotation = 24 hour = 24 × 3600

                                                       = 86400 s

distance = speed × time

hence, the velocity of the student is equal to

The speed(v) of a physics student in Miami, Florida is 418.32 m/sec

From the given information;

The radius of the physics student at latitude 26° can be computed as:

= 6400 cos(26°) × 1000 m

= 6400 (0.89879) × 1000 m

Assuming the circumference of the rotation  represents the distance which is:

= 2πr

= 2π (6400 (0.89879) × 1000 m)

Then, using the relation:

Speed = distance/ time

where;

Then, the speed of the physics student in Miami is:

Speed = 2π 6400 (0.89879) × 1000 m /  86400 sec.

Speed = 418.32 m/sec

Learn more about rotational speed here:

link

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

explanation:

newton's third law, for every action there is an equal and opposite reaction.