Outside the space shuttle, you and a friend pull on two ropes to dock a satellite whose mass is 700 kg. the satellite is initially at position < 3.3, -1.6, 2.0> m and has a speed of 6 m/s. you exert a force < -400, 500, 250> n. when the satellite reaches the position < 2.3, 2.6, -11.8> m, its speed is 6.18 m/s. how much work did your friend do?

your friend did a work of 1717.34 J

Explanation:

The sum of the work made by your friend and you is equal the change in the kinetic energy, so:

Where is the work that you did, is the work that your friend did, m is the mass of the satellite and and are the final and initial speeds

Additionally the work that you did is equal to:

Where F and s are vectors. So, the vector s that said the displacement is calculated as:

s = <2.3, 2.6, -11.8> - <3.3, -1.6, 2.0>

s = <-1 , 4.2 , -13.8>

Therefore, is:

Then, replacing the values on initial equation and solving for , we get:

Finally, your friend did a work of 1717.34 J

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