Aspace shuttle is approaching the surface of the moon to land. it approaches the moons surface with an initial velocity of 28m/s and is slowing at a rate of -2m/s^2. show all work and units for problems. a) draw velocity vs time graph
b) when will shuttles velocity equal zero?
c) how far above the surface of the moon was the shuttle when it began to slow down?

Explanation:

a ) Velocity vs time graph will be a straight line with negative slope , making a slope of 2 because slope of v-t graph gives the value of acceleration.

b ) v = 0 , u = 28 m/s

t = ?

v = u - at

0 = 28 - 2 t

t = 14 s

shuttle velocity will become zero after 14 sec.

c ) v ² = u² - 2 a s

0 = 28² - 2 x 2 x s

s = 28² / 4

= 196 m .

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)