A"moving sidewalk" in an airport terminal building moves at a speed of 1.2 m/s and is of length 36.0 m . a woman steps on at one end and walks at a speed 1.6 m/s relative to the moving sidewalk. a. how much time does she require to walk from one end to the other if she walks in the same direction the sidewalk is moving?
b. how much time does she require to walk from one end to the other if she walks opposite to the direction the sidewalk is moving? express your answer using two significant figures.

13 seconds

90 seconds

Explanation:

=Velocity of sidewalk = 1.2 m/s

=Velocity of woman = 1.6 m/s

Distance to travel = 36 m

Time = Distance / Speed

Time taken by the woman if she walks in the same direction the sidewalk is moving is 13 seconds

Time taken by the woman if she walks opposite to the direction the sidewalk is moving is 90 seconds

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer