Aboy is standing bridge and releases a ball from a height of 10 m, while a boat is approaching at a constant 15 on a m/s. how far away must the boat be from the release point of the ball for the ball to land in the boat?

Explanation:

given,

height of the bridge = 10 m

constant speed of boat = 15 m/s

distance of the boat from the release point = ?

initial velocity of ball = 0

time taken by the ball to reach down

t = 1.43 s

distance travel by the boat in 1.43 second

s = v × t

s = 15 × 1.43

s = 21.45 m

boat distance from the release point

d = 23.67 m

distance of boat from the release point = 23.67 m

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s