The warthog escapes! (3 pts) a slow prey animal may be able to escape from a fast predator if the prey is sufficiently nimble and is able to turn with a tight radius. a) if an animal with mass m is running with a speed v on ground where the coefficient of static friction between the animal’s hooves and the ground is μs, derive an expression for the minimum turning radius r for that animal, assuming it maintains a constant speed throughout the turn. (fanclan! )b) a lioness with mass m2 = 120 kg is running with a speed of v2 = 15 m/s and is just about to catch a warthog with mass m1 = 80 kg running with a speed of v1 = 10 m/s. as an evasive maneuver, the warthog executes his tightest possible 180° turn with a radius r1 while maintaining his speed v1, and then continues to run in a straight line at speed v1. the lioness attempts her tightest possible 180° turn with a radius r2 at a speed of v2, and then continues to run in a straight line at speed v2. if both animals have a coefficient of static friction of μs = 0.5 between their feet and the ground, what are the radii r1 and r2? the lioness and warthog are pictured below and the situation is illustrated in the diagram below. c) at the moment when the lioness has just completed her 180° turn, what is thedistance between the lion and the warthog? (note that the warthog will complete his turnbefore the lioness, so he will have been running in a straight line at 10 m/s for someperiod of time when the lioness completes her turn.) assume that the distance betweenthem was zero when they both began their turns. such a maneuver may allow the warthogto escape!