Abucket of water of mass 14.0 kg is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter 0.260 m with mass 12.1 kg . the cylinder pivots on a frictionless axle through its center. the bucket is released from rest at the top of a well and falls a distance 10.7 m to the water. you can ignore the weight of the rope.

The tension in the rope is 41.38 N.

Explanation:

Given that,

Mass of bucket of water = 14.0 kg

Diameter of cylinder = 0.260 m

Mass of cylinder = 12.1 kg

Distance = 10.7 m

Suppose we need to find that,

What is the tension in the rope while the bucket is falling

We need to calculate the acceleration

Using relation of torque

Where, I = moment of inertia

= angular acceleration

...(I)

Here, F = tension

The force is

...(II)

Where, F = tension

a = acceleration

From equation (I) and (II)

Put the value into the formula

We need to calculate the tension in the rope

Using equation (I)

Put the value into the formula

Hence, The tension in the rope is 41.38 N.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever